ANSWER: The newest magnetized push towards the a moving charges is always perpendicular so you’re able to its speed
Then force would be F=kqvB from the z-guidance
QUESTION: An amount of electrical power is defined by the volts x amps x go out. A number of physical opportunity would-be discussed (or is) by the force x range and this equates to kinetic times. When electrical energy try converted into physical, a power will be produced by using current and you will most recent (amps). Is it a paradox? Power is functionally force x time while you are technical energy sources are force x range.
ANSWER: step 1 V=step one J/C and you can step one A=1 C/s, thus step one volt ·amp·second=step 1 Joules=force·range. No difference, zero paradox. A different way to consider this would be the fact current minutes voltage is actually fuel and you may stamina are W=J/s.
Follow-up Matter: We completely just remember that , step one amplifier are step one coulomb for every next. I don’t know where step one volt is equivalent to step one joule for each and every coulomb comes from otherwise why that’s true.
ANSWER: This new digital field Elizabeth is placed become the force F thought from the a charge Q divided of the Q. The new electric potential V means Elizabeth moments length d over it serves. V=Ed=Fd/Q=[J/C]
QUESTION: magnetized push towards the costs q swinging having velocity v =qV x B easily to see it fees regarding a vehicle moving which have same rate and you will recommendations just like the regarding q than they acceleration because observed from the myself could well be 0 so that the force will be 0.i am not able to understand this issues at any given time force low no and also at other big date it’s 0
ANSWER: The problem is that the digital and you can magnetic industries in a single figure off site won’t be the same like in some other moving body type. (This really is special relativity.) For you personally you first start with a magnetic profession and no electric field. Imagine that brand new magnetized career is in the y-direction, B=jB, E=0, together with velocity away from q is in the x-direction, v=iv. From the swinging frame the brand new sphere is B’=j?B and you will E’=k?vB, in which ?=1/ v(1-(v/c) dos ). Observe that E’=v x B’; additionally the force, since found in the fresh moving body type is actually F’=qE’=qv x B’=k?qvB, to put it mildly. Notice, yet not, you to definitely F’ ?F , they differ by the a very important factor out of ?; it is because force is alleged getting perhaps not Lorentz invariant and is also not a useful wide variety inside relativity.
QUESTION: Basically fool around with particular magnetized bars, slash him or her really well in order for I can place them together in order to form a world, with the exact same pole leading outward, therefore the almost every other rod leading inward, carry out I get a charismatic monopole object?
ANSWER: Think of your bars as dipoles of positive and negative magnetic charges (monopoles) separated by a distance d. The magnitude of the magnetic field B of a monopole is inversely proportional to the square of the distance r from the charge, B=kq/r 2 where k is some constant. In the drawing above the field at point p is B=B-q+B+q=kq[(1/(r-d) 2 -(1/r+d) 2 ]=4kqrd/[(r+d) 2 (r-d) 2 ]. The field does not look like a monopole because it falls off like 1/r 3 , not 1/r 2 .
Now, glance at the career whenever r>>d: B?4kqd/r step three
QUESTION: Assume I’ve a fee +q and there is a spot P , Guess We put an excellent conductor involving the charges +q and you may P . Because there are 100 % free electrons with it , Bad electrons circulate to the +q and you can equal positive Threesome Sites dating online charges in the conductor near P , The conductor have costs shipments instance good dipole. Therefore if I wish to estimate E field from the P . I am able to explore superposition concept to locate E within P due so you’re able to +q and you can Age on account of dipole. However, Gauss’s rules says you to definitely dipole will not lead almost anything to E profession in the P. Do you establish me ‘intuitively’ (Not in equations) why new dipole wont lead anything to industry in the P ?